Getting n alone in n!=x and nlgn=x

  • Thread starter Dafydd
  • Start date
  • #1
12
0

Homework Statement



I need to know the greatest n for which n! is greater or equal to x, and the greatest n for which nlgn is greater or equal to x.

Homework Equations



Can't think of any. Sorry!

The Attempt at a Solution



For a "normal" function, like, say, lgn or n^2, it would be as easy as inverting the function and getting n on its own, like this:

lgn = x
n = 2^x (where lg is of base 2)

or

n^2 = x
n = sqrt(x).

However, for n!=x and nlgn=x I can't come up with a way to do this. Help!
 

Answers and Replies

Related Threads on Getting n alone in n!=x and nlgn=x

Replies
3
Views
27K
  • Last Post
Replies
3
Views
921
  • Last Post
Replies
6
Views
1K
  • Last Post
Replies
14
Views
16K
  • Last Post
Replies
8
Views
1K
  • Last Post
Replies
2
Views
756
Replies
13
Views
2K
Replies
7
Views
3K
Top