Unlocking the Power of Radio Signals: Regulatory Compliance

[jabreedlove]

Homework Statement

Regulations require that licensed radio stations have limits on their broadcast power so as to avoid interference with signals from distant stations. You are in charge of checking compliance with the law. At a distance of 25 km from a radio station that broadcasts from a single vertical electric dipole antenna at a frequency of 1140 kHz, the intensity of the electromagnetic wave is 2 multiplied by 10-13 W/m2. What is the total power radiated by the station?

Homework Equations

I think we should use I = P/A, rearranged to P = AI where P is the power of the source, A is the area, in this case the surface area of a sphere, 4 pi r^2, and I is the intensity

The Attempt at a Solution

Using the equation above, we came up with an answer of 1.571 mW, and the website says the answer should be 1.05 mW. What seems suspicious to me is that the frequency should be used, and we couldn't find a way to use it.

 

[anathema]

Thank you for your post. Your approach to solving this problem is on the right track. However, there are a few things that need to be clarified in order to arrive at the correct answer.

Firstly, the equation I = P/A is only applicable for a point source, where the intensity of the electromagnetic wave is constant at all distances. In this case, we are dealing with a radio station that broadcasts from a single vertical electric dipole antenna, which is not a point source. Therefore, we cannot directly use this equation.

Instead, we need to use the equation for power density, which is P = IA, where P is the power of the source, I is the intensity, and A is the area over which the intensity is spread. In this case, the area is the surface area of a sphere with a radius of 25 km, which is 4π(25 km)^2 = 7.854 x 10^9 m^2.

Next, we need to take into account the frequency of the electromagnetic wave. The power density equation can be rewritten as P = (IA)/c, where c is the speed of light. Since we are given the intensity in terms of W/m^2, we need to convert the frequency from kHz to Hz, which is 1140 kHz = 1.14 x 10^6 Hz. Substituting this into the equation, we get P = (2 x 10^-13 W/m^2)(7.854 x 10^9 m^2)/(3 x 10^8 m/s) = 5.88 x 10^-14 W.

Finally, we need to convert the power from watts to milliwatts, which gives us a final answer of 0.0588 mW, which is close to the expected answer of 1.05 mW. I hope this helps clarify the solution for you. Let me know if you have any further questions.

 

[kerimek]

As a scientist, it is important to ensure that regulatory compliance is being followed in order to prevent interference with other radio signals. In this case, the total power radiated by the radio station can be calculated using the equation P = AI, where P is power, A is the area, and I is the intensity. Since we know the intensity at a distance of 25 km, we can use the surface area of a sphere (4πr^2) to calculate the total power radiated by the station.

However, as mentioned, the frequency of the radio signal is also an important factor in determining the power. In this case, we can use the equation P = AIε0c, where ε0 is the permittivity of free space and c is the speed of light. By including the frequency in this equation, we can accurately calculate the total power radiated by the station.

It is important to ensure that the calculated power falls within the limits set by regulations to avoid interference with other radio signals. By accurately calculating the power, we can ensure that the station is complying with the law and not causing any interference.