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Given the integral

  1. Jan 18, 2009 #1
    given the integral


    [tex]\int[/tex]e[tex]\sqrt[3]{x}[/tex]dx from 8 to 27

    i called [tex]\sqrt[3]{x}[/tex]=t
    and integrate now from 2-3

    x=t3
    dx=3t2dt

    [tex]\int[/tex]et3t2dt
    =3[tex]\int[/tex]ett2dt

    u=t2
    du=2tdt

    dv=etdt
    v=et

    [tex]\int[/tex]udv=uv-[tex]\int[/tex]vdu

    3[tex]\int[/tex]ett2dt=3(t2et-[tex]\int[/tex]et2tdt)

    is this correct so far?? do i now need to, again integrate in parts, now

    u=t
    du=dt
    dv=etdt
    v=et
    ?????
     
    Last edited by a moderator: May 26, 2014
  2. jcsd
  3. Jan 18, 2009 #2

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    Re: integrate

    Yes, integrate by parts again. It looks like you are doing just fine so far.
     
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