# Given the integral

1. Jan 18, 2009

### Dell

given the integral

$$\int$$e$$\sqrt[3]{x}$$dx from 8 to 27

i called $$\sqrt[3]{x}$$=t
and integrate now from 2-3

x=t3
dx=3t2dt

$$\int$$et3t2dt
=3$$\int$$ett2dt

u=t2
du=2tdt

dv=etdt
v=et

$$\int$$udv=uv-$$\int$$vdu

3$$\int$$ett2dt=3(t2et-$$\int$$et2tdt)

is this correct so far?? do i now need to, again integrate in parts, now

u=t
du=dt
dv=etdt
v=et
?????

Last edited by a moderator: May 26, 2014
2. Jan 18, 2009

### Dick

Re: integrate

Yes, integrate by parts again. It looks like you are doing just fine so far.