Given the uncertainty in momentum, calculate the uncertainty in Energy

In summary, to find the uncertainty in energy, you can use the wave equation and the given formula for energy to calculate the expectation value of E^2. Then, use this value and the given formula for <E> to solve for ΔE.
  • #1
datran
14
0

Homework Statement



I am given that E = (hbar)^2 k^2 / 2m. I am suppose to calculate the uncertainty in energy(ΔE).

I am also given the wave equation.

I am given Δp (uncertainty in p), Ko (wave number). and that Δp << hbar Ko.

Homework Equations



I believe the equation is ΔE = sqrt(<E^2> - <E>^2).

The Attempt at a Solution



So I found <E> = <p^2> / 2m. How am I suppose to find <E^2>? I tried to just square the given E formula and then find <E^2> that way. However, I get <hbar^4 k^4 > / 4m^2. I do not know what to do from there.

Any help would be great. Thanks!
 
Physics news on Phys.org
  • #2


Hello,

To calculate <E^2>, you can use the wave equation and the given formula for E. First, plug in the given E formula into the wave equation to obtain:

Ψ = A * exp(i(kx - ωt))

Where A is the amplitude, k is the wave number, and ω is the angular frequency. Now, to find <E^2>, we need to take the expectation value of E^2, which is:

<E^2> = ∫ Ψ*E^2 Ψ dx

Using the given formula for E, we can simplify this to:

<E^2> = (∫ Ψ* (hbar)^2 k^2 / 2m Ψ dx)^2

= (hbar)^4 k^4 / 4m^2 * (∫ Ψ* Ψ dx)^2

= (hbar)^4 k^4 / 4m^2 * (Ψ* Ψ)^2

= (hbar)^4 k^4 / 4m^2 * A^4

= (hbar)^4 k^4 / 4m^2 * |A|^4

= (hbar)^4 k^4 / 4m^2 * (|A|^2)^2

= (hbar)^4 k^4 / 4m^2 * 1

= (hbar)^4 k^4 / 4m^2

Therefore, <E^2> = (hbar)^4 k^4 / 4m^2. Now, using this and the given formula for <E>, you can plug these values into the formula for ΔE and solve for the uncertainty in energy. I hope this helps! Let me know if you have any further questions.
 

1. What is the uncertainty principle?

The uncertainty principle is a fundamental principle in quantum mechanics that states that it is impossible to know the exact position and momentum of a particle simultaneously.

2. How does the uncertainty principle relate to momentum and energy?

The uncertainty principle states that there is a fundamental limit to how accurately we can measure the momentum and position of a particle. This means that there will always be some uncertainty in the measurement of momentum, which in turn leads to uncertainty in the measurement of energy.

3. Why is there an uncertainty in momentum?

This uncertainty arises from the wave-particle duality of matter. In quantum mechanics, particles can behave as both particles and waves, and the more accurately we measure the position of a particle, the less accurately we can measure its momentum.

4. How is the uncertainty in energy calculated?

The uncertainty in energy is calculated using the Heisenberg uncertainty principle, which states that the product of the uncertainties in position and momentum must be greater than or equal to a constant value known as Planck's constant. Therefore, the uncertainty in energy can be calculated by finding the product of the uncertainties in position and momentum and multiplying it by Planck's constant.

5. What are the practical implications of the uncertainty in energy?

The uncertainty in energy has significant implications in many areas of physics, including atomic and nuclear physics. It also plays a crucial role in the development of technologies such as quantum computing, where the manipulation of particles at the quantum level is necessary. Additionally, it has implications in understanding the behavior of subatomic particles and the nature of the universe.

Similar threads

  • Advanced Physics Homework Help
Replies
5
Views
863
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
7
Views
1K
  • Advanced Physics Homework Help
Replies
4
Views
916
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
30
Views
1K
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
877
Back
Top