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Glan-Thompson polarizator

  1. Nov 25, 2011 #1

    I understand why a Glan-Thompson polarizator (http://www.thorlabs.de/newgrouppage9.cfm?objectgroup_id=116) works, i.e. birefringence. Currently I am sending light through one, and the beam that goes straight out has a Brewster angle, i.e. it must be polarized parallel to the plane of incidence.

    When I turn the polarizator around its axis, then the Brewster angle disappears. I don't understand that, and I can't find the explanation in any of my books on optics. Can anyone help out?

    Last edited: Nov 25, 2011
  2. jcsd
  3. Nov 26, 2011 #2
    I guess its basically a question of what happens when I change the angle between the optic axis and the propagation direction, but how does that change what component comes out where?
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