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Golf ball

  1. Aug 30, 2007 #1
    A golf ball released from a height of 1.76 m above a concrete floor, bounces back to a height of 0.80 m. If the ball is in contact with the floor for 4.62 ms, what is the magnitude of the average acceleration a of the ball while it is in contact with the floor?


    4.9x^2-1.76

    I used this to determine how long it would take for the ball to get to .08m. Apparently it will take .7228 s.

    Outside of that, I'm not really sure what to do. Is there a way to relate position to velocity? And what exactly is the magnitude of the average acceleration? I haven't heard that term at all until this question.
     
  2. jcsd
  3. Aug 31, 2007 #2

    learningphysics

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    What is the velocity before the ball hits the ground when it's dropped from 1.76m?
     
  4. Aug 31, 2007 #3

    learningphysics

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    You should be familiar with this equation:

    [tex]v_{2}^2 = v_{1}^2 + 2as[/tex] where s is the displacement.
     
  5. Aug 31, 2007 #4
    I actually gave you all my givens, unless I'm suppose to calculate velocity.
     
  6. Aug 31, 2007 #5
    Is it 9.799 m/s^2
     
  7. Aug 31, 2007 #6
    okay, i keep getting ansewrs in the 23.86 range, however they seem to be wrong
     
  8. Aug 31, 2007 #7

    learningphysics

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    Yes, calculate the velocity right before it hits the ground... use the formula I posted.
     
  9. Aug 31, 2007 #8
    okay using that formula, i got 17.924 as the average acceleration
     
  10. Aug 31, 2007 #9
    actually i took the acceleration of both sides and then took the average
     
  11. Aug 31, 2007 #10

    learningphysics

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    No, that's not right. Can you post your work? What did you get for the velocity before the ball hits the ground?
     
  12. Aug 31, 2007 #11
    4.9x^2-1.76=0
    x=.5993

    9.8(.5593)=5.873 m/s at the point of impact

    would i have to do something similar for the other side?
     
  13. Aug 31, 2007 #12

    learningphysics

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    Exactly... find the initial velocity during the path when the ball goes upwards to 0.80m. ie: the velocity right after it bounces up.
     
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