Golf Projectile Motion problem

[deaninator]

1. Homework Statement
A golfer rips a tee shot from an elevated driving range tee-off such that the ball leaves horizontally. The ball lands exactly at the 66.8 meter marker, and was shot from the upper level (6.5 meters above the ground).

How long was the ball in the air?

And how fast did the ball leave the tee?


2. Homework Equations
X = VoxT


3. The Attempt at a Solution
My teacher did a terrible job touching base on projectile motion... where do i start?

 

[zgozvrm]

How long does it take an object to drop 6.5 meters from rest?

 

[deaninator]

How long does it take an object to drop 6.5 meters from rest?

I know that the question is asking that...but can you please elaborate?

 

[tiny-tim]

hi deaninator!

A golfer rips a tee shot from an elevated driving range tee-off such that the ball leaves horizontally …

use the standard constant acceleration equations for components of motion in the vertical (y) direction, with a = -g

 

[rwisz]

I would first gather all the necessary information from the given problem. In this case, we know that the golfer hits the ball horizontally from an elevated tee-off, the ball lands at a certain distance (66.8 meters) and the tee-off was at a certain height (6.5 meters).

To solve for the time in the air, we can use the equation X = VoxT, where X is the distance, Vox is the initial velocity in the horizontal direction, and T is the time. We know the distance (66.8 meters) and the initial velocity in the horizontal direction is 0 m/s since the ball was hit horizontally. Therefore, we can solve for T by rearranging the equation to T = X/Vox.

To solve for the initial velocity, we can use the equation V = Vo + at, where V is the final velocity, Vo is the initial velocity, a is the acceleration (in this case, due to gravity), and t is the time. We know the final velocity is 0 m/s since the ball lands, the initial velocity is what we are solving for, and the acceleration is -9.8 m/s^2 (assuming no air resistance). Therefore, we can solve for Vo by rearranging the equation to Vo = V + at and plugging in the values we know.

In summary, to solve for the time in the air, we can use X = VoxT and to solve for the initial velocity, we can use V = Vo + at. It is important to note that these equations assume ideal conditions and do not take into account factors such as air resistance. Additionally, it would be helpful to have a basic understanding of projectile motion and its equations before attempting to solve this problem.