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Got another one for you

  1. Nov 26, 2007 #1
    1. The problem statement, all variables and given/known data

    A rotating door is made from four rectangular glass panes, as shown in the drawing. The mass of each pane is 92 kg. A person pushes on the outer edge of one pane with a force of F = 79 N that is directed perpendicular to the pane. Determine the magnitude of the door's angular acceleration.


    2. Relevant equations

    [tex]\sum T = I\alpha[/tex]

    [tex]I = (1/12)ML^{2}[/tex]

    3. The attempt at a solution
    [tex]T[/tex] = 79(1.2) = 94.8

    94.8 = (1/12)(92)(2.4)[tex]^{2}[/tex] [tex]\alpha[/tex]
    94.8 = 44.16[tex]\alpha[/tex]
    2.15 = [tex]\alpha[/tex]

    the alphas aren't supposed to be superscript...anyway.....this is my answer and it's wrong...don't know what i'm doing ...or not doing...
    Last edited by a moderator: Apr 23, 2017
  2. jcsd
  3. Nov 26, 2007 #2


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    The torque imposed by the person pushing with a force of 79N is correct.
  4. Nov 26, 2007 #3
    Where am I going wrong?
    Last edited: Nov 26, 2007
  5. Nov 26, 2007 #4
    nevermind...I got it..I didn't realize I would take 92 x 4 to use as the weight
  6. Nov 26, 2007 #5


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