(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Calculate the electric potential due to a tiny dipole whose dipole moment is 6.0×10^−30 C*m at a point 3.6×10^−9 m away for the following cases.

a) This point is along the axis of the dipole nearer the positive charge.

b) This point is 45 degrees above the axis but nearer the positive charge.

c) This point is 45 degrees above the axis but nearer the negative charge. Let V = 0 at r = infinity .

2. Relevant equations

For part a) I used p = q*d, where p is the dipole moment, q is the charge, and d is displacement. Then used (1/(4*pi*E))*(q/d), where E is the permittivity of free space constant, 8.85 x 10^-12

For part b) I got stuck on this part, I know I have to use the given 45 degrees, perhaps to find a new value for d?

Im not as familiar as I would like to be with the subject, any help or explanation welcome.

3. The attempt at a solution

a) V = 4.2 x 10^-3

b) V = ?

c) V = ?

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# Homework Help: Got stuck need help! Electric Potential due to Dipole

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