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Introductory Physics Homework Help
GPE and gravitational force exerted by a ring
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[QUOTE="GwtBc, post: 5451603, member: 470790"] It is nasty, but my calculator doesn't mind that. Also the denominator 'r' terms is supposed to be 'r^2' in the integral. Aren't I essentially finding the initial and final GPEs and then taking the difference? How else can I find the GPE? [/QUOTE]
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Introductory Physics Homework Help
GPE and gravitational force exerted by a ring
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