1. The problem statement, all variables and given/known data A box of mass 6.2 kg slides 4.8 m down a ramp that is inclined 38 degrees to the horizontal. What is the velocity of the box right before it hits the ground? Mass=6.2 Height=dsintheta? V=is what needs to be found theta=38 2. Relevant equations GPE=mgh=mgdsin(theta) KE=1/2mv^2 New equation: GPE⋅+KE⋅=GPE mgh⋅+1/2mv^2=mgh 1/2mv^2=mgh-mgh⋅ mv^2=2(mgh-mgh⋅) V^2=2(mgh-mgh⋅)/m v=√2(mgh-mgh⋅)/m 3. The attempt at a solution i just want to see if my equations are correct. if it could be factored even more could someone tell me. like the two mgh's i feel like could be changed but im not too sure. I know h is also h=dsin(θ) but would it be the same for the two since it will be different?