Jack went up a hill to fetch water. Jack fell down and rolled down the hill accelerating at 0.65 m/s^2 down. If he rolled 11m down the hill in 3.7s, with what velocity was he moving when he fell?
a = v2 - v1/t
v2 = at + v1
The Attempt at a Solution
(0.65m/s^2)(3.7s) + 11
= 13.5 m/s.
I solved for v2, the velocity when he reached the bottom of the hill.
However the answer says 1.8m/s.
What am I doing wrong? Am I supposed to be looking for something else, not v2?
Even if I solved for v1, I would get a negative answer.
As usual, I am so confused. :yuck: