- #1

SoConfused__

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## Homework Statement

Jack went up a hill to fetch water. Jack fell down and rolled down the hill accelerating at 0.65 m/s^2 down. If he rolled 11m down the hill in 3.7s, with what velocity was he moving when he fell?

## Homework Equations

a = v2 - v1/t

v2 = at + v1

## The Attempt at a Solution

(0.65m/s^2)(3.7s) + 11

= 13.5 m/s.

I solved for v2, the velocity when he reached the bottom of the hill.

However the answer says 1.8m/s.

What am I doing wrong? Am I supposed to be looking for something else, not v2?

Even if I solved for v1, I would get a negative answer.

As usual, I am so confused. :yuck: