- #1
JackandJones
- 16
- 0
A delivery truck drives 14.0 km [E], 6.0 km [N], 12.0 km [ N 15° E], and then 2.0 km [N 65° E]. This takes him 42 minutes. Calculate the truck's distance and displacement.
When you draw this diagram you basically get two triangles. One large triangle and one smaller triangle. You need to find displacement. For the large triangle you can use pythagorean theorem, for the small triangle---that is where I am having problems.
I split 12 km (N 15 degrees E) into components: so I got 12 x sin (15) and 12 x cos (15) for the one small triangle
I split 2 km (N 65 degrees E) into components so I got 2 x sin (65), and 2 x cos (65)
So the total for x = 4.92 km and y = 12. 45 km...
Now what do I do?? I was thinking Cosline Law: but I don't know what to sub in for Cos.
Any help is appreciated!
When you draw this diagram you basically get two triangles. One large triangle and one smaller triangle. You need to find displacement. For the large triangle you can use pythagorean theorem, for the small triangle---that is where I am having problems.
I split 12 km (N 15 degrees E) into components: so I got 12 x sin (15) and 12 x cos (15) for the one small triangle
I split 2 km (N 65 degrees E) into components so I got 2 x sin (65), and 2 x cos (65)
So the total for x = 4.92 km and y = 12. 45 km...
Now what do I do?? I was thinking Cosline Law: but I don't know what to sub in for Cos.
Any help is appreciated!