1. The problem statement, all variables and given/known data 2 men with mass of 100kg each, are on a stationary cart with mass of 300 kg. The cart has no friction withthe tracks. The cart can only go north and south. 1st man starts runnin at speed of 5 m/s(reletive to cart) towards north and jumps off the cart. Otherman runs with same speed (reletive to cart) towards the south after the 1st man what is the cart final velocity?? 2. Relevant equations use the equation of Conservation of energy Coservation of momentum 3. The attempt at a solution North is positive M1 = 100 M2 = 100 M3 = 300 MAN 1 m1v1 +m2v2 + m3v3 = m1v1' +m2v2' + m3v3' 100(5)+ 0+0 = V'(100+300) 500/400 = v' 10.25 m/s =v' MAN 2 m2v2 + m3v3 = m2v2' + m3v3' 100(-5) + 300(1.25) = 300v' -500+375 = 300v' -0.41666 m/s = v' NOW I need someone to proof read this and tell me wht to do next please!! Teh final asnwer is 0.25 m/s North!!!