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Gradient function?

  1. Mar 27, 2005 #1
    I was reading this ebook when I found Coulomb's law:
    http://www.brokendream.net/xh4/elec.jpg
    What I'm unsure of is how the gradient function applied to 1/|x-x'| is the same thing as |x-x'|/|x-x'|^3...
    I know what the gradient function is but I'm totally lost as to how the formula was transformed that way..
    Can anyone care to explain?
    Thanks alot.
     
    Last edited by a moderator: Apr 21, 2017
  2. jcsd
  3. Mar 27, 2005 #2

    dextercioby

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    Compute

    [tex] \nabla_{\vec{r}}\left(\frac{1}{r}\right) [/tex]

    ,for

    [tex] r=:\sqrt{(x-x')^{2}+(y-y')^{2}+(z-z')^{2}} [/tex]

    and

    [tex] \nabla_{\vec{r}}=\frac{\partial}{\partial x} \vec{i}+ \frac{\partial}{\partial y} \vec{j} +\frac{\partial}{\partial z} \vec{k} [/tex]

    Daniel.
     
    Last edited: Mar 27, 2005
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