gradient of the stationary points of y=1-2sinx domain 0<x<2pi
The Attempt at a Solution
dy/dx = -2cosx
Gradient of the stationary point? Do you need to find that or the gradient? Because when you put dy/dx=0 it sort of implies what the gradient will be.
Sorry. the qu reads 'the curve y=1-2sinx has domain 0<x<pi. find the gradients of the curve at the points where the curve crosses the x-axis