1. The problem statement, all variables and given/known data A hiker climbs a mountain whose height is given by z = 1000 - 2x2 - 3y2. When the hiker is at point (1,1,995), she moves on the path of steepest ascent. If she continues to move on this path, show that the projection of this path on the xy-plane is y = x3/2 2. Relevant equations 3. The attempt at a solution The path of steepest ascent is in the direction in which she would ascent as rapidly as possible, aka the gradient vector. gradf = fx i + fy j = -4x i -6y j gradf at (1,1,995) = -4 i - 6 j What now?