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Precalculus Mathematics Homework Help
Graph of double absolute values
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[QUOTE="robertmatthew, post: 4492961, member: 453357"] [h2]Homework Statement [/h2] |x| + |y| ≤ 1 What is the region in the plane that solves this inequality? [h2]Homework Equations[/h2] [h2]The Attempt at a Solution[/h2] I first tried graphing it by isolating the y variable |y| ≤ -|x| + 1 Then I looked at the hint we were given, which was to assume that x and y are both positive, so I treated it as if it were written y ≤ -x+1 And then constructed a graph of a line that was basically y = -x+1 with a domain of [0,3] But then what threw me off is that the y variable does have the absolute value bars, so there can't be negative y values in the graph, right? So now I'm thinking I just have to flip the part of the graph so that it more closely resembles y=|x-1| in the domain of [0,3]. Is that correct or am I completely missing this? [/QUOTE]
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Precalculus Mathematics Homework Help
Graph of double absolute values
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