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## Homework Statement

Draw a probable graph of ln (A/R) vs 1/T.

## Homework Equations

Arrhenius equation: k= Ae

^{-E/RT}

## The Attempt at a Solution

Taking natural log on both sides of arrhenius equation :

ln k = ln A - E/RT

ln k - ln R = ln A - E/RT - ln R (subtracting ln R from both sides)

ln (k/R) = ln (A/R) - E/RT

rearranging terms and comparing it with y=mx + c,

c= ln (k/R) and m = E/R

According to me the graph should be like this. In the answers, the graph is a similar one, except that there is no intercept given. I am confused. Any help is appreciated.