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Graphing a plane

  1. Sep 8, 2013 #1
    Hey, how would I graph the plane x + 2y + 3z = 0. We were taught to find the x,y and z intercepts and then connect them resulting in the plane. In the following equation, I get the points x=0,y=0 and z =0. I can see that the intercept approach doesn't work for this question. What else can I try?
     
  2. jcsd
  3. Sep 8, 2013 #2

    tiny-tim

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    hi baddin! :smile:
    easy-peasy

    draw the line x + 2y = 0 on the x-y-plane, and the line x + 3z = 0 on the x-z-plane, and join them :wink:
     
  4. Sep 8, 2013 #3
    Thanks for your help, it looks correct! =D
     
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