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Graphing Conic Section

  1. Aug 18, 2010 #1
    What's the process that needs to take place to be able to graph the following equation (not-using a graphing calculator):
    x2 + 12xy + 36y2 + 2x - 3y - 9 = 0

    I know to use the B2 - 4AC formula to identify the equation as being parabolic, though I don't understand the formula...

    Looking at the equation at first, I thought you could factor it to resemble something like:
    (x2 = y or y2 = x)

    But, that's where my thinking ended (or maybe it never actually began...)


    Thanks!
     
  2. jcsd
  3. Aug 18, 2010 #2

    mathman

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    Science Advisor

    It's parabolic, but the axis of symmetry is not parallel to either the x or y axis,
     
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