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Homework Help: Graphing Help Needed

  1. Feb 23, 2005 #1
    i need to graph f(x)=2^2+9/5x^2+2

    the vertical asym. would be the i squareroot10/2 ?

    if that is correct how do i graph an imaginary #
  2. jcsd
  3. Feb 23, 2005 #2
    You're telling me you need to graph


  4. Feb 23, 2005 #3
    no in the numerator is: 2x^2+9
    denomorator is: 5x^2+2
  5. Feb 23, 2005 #4
    So it is


    and you have to sketch the graph?
  6. Feb 23, 2005 #5
    It has horizontal asymptote at y=2/5 and no vertical asymptotes since the denominator is never zero.
  7. Feb 24, 2005 #6
    thank you very much
  8. Feb 24, 2005 #7


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    Science Advisor
    Homework Helper

    Yes,asymptotes (especially vertical ones) refer to REAL values for numbers...

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