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Graphing in vertex form?

  1. Apr 15, 2015 #1
    I've run into stumbling block here, is some sort of conversion required when your equation looks like: (x+1/2)^2 = 12(y - 3). Do I move it to standard form or can I graph it as is?
     
  2. jcsd
  3. Apr 15, 2015 #2

    robphy

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    The answer might depend on your skill in graphing.
    Usually, it's easier to isolate one variable [now called the dependent] in terms of another variable [the independent].
    Then you can run different values for the independent variable and quickly get the corrseponding values for the dependent one.
    Some software, like the desmos calculator, can handle your original "implicit form".
     
  4. Apr 15, 2015 #3
    That's what I was going to do, I just wanted to make sure. Thank you.
     
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