1. The problem statement, all variables and given/known data Why did we choose to linearize our data by plotting velocity versus time rather than by distance versus time-squared. Use d-v-a-t (distance=velocity*time+0.5*acceleartion*time-squared) equations to present a convincing answer. 2. Relevant equations 1. d=vt+1/2at^2 2. (v2)=(v1)+at 3. (v2)^2-(v1)^2=2ad 4. d=1/2(v1+v2)*t V1 is initial velocity v2 is final velocity t is time a is acceleration d is distance 3. The attempt at a solution I must say that I am perplexed since they are essential the same graphic shape and equivalent slopes (which equals accleration if you take derivative). I guess that it could have something to do with my 3rd equation above.What has got me is that v vs. t and d vs. t^2 are both linear graphs! Is it because acceleration is defined as the change in velocity divided by the change in time and not change in distance divided by change in time squared. But that doesn't use a d-v-a-t equation. Help please. Thanks in advance for your time and thoughts.