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Collegestudent5

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Three point particles are fixed in position in an xy plane. Two of them, particle A of mass 6.00g and particle B of mass 12.0g, are shown in Fig12-38 (the figure has A at the origin and B 30 degrees above the negative side of the x-axis) with a separation of dAB=.500m at angle 30 degrees. Particle C, with mass 8.00g, is not shown. The net gravitational force acting on particle A due to particles B and C is 2.77x10^-14N at an angle of -163.8 degrees from the positive direction of the x axis. What are (a) the x coordinate and (b) the y coordinate of particle C?

I tried to solve a system of two equations since the problem gave us Fnet=2.77x10^.14N and the angle=-163.8 degrees:

Fnet=(Fx^2+Fy^2)^1/2 and Tan(0)=y/x

but i sill could not find the solution.

Thanks for the help in advance.