- #1
noamriemer
- 50
- 0
Hello! I fail to understand this question... I don't even know how to approach it...
Given: [tex] m\frac{d^{2}x^{\mu}} {d\tau^{2}} =e{F^{\mu}_{nu}} \frac{dx^{\nu}} {d\tau}[/tex]
I have to define [tex]u^{\mu}= \frac {dx^{\mu}} {d\tau^2}[/tex]
and obtain:
[tex]u^0= cosh(\frac {eE\tau} {m}) u^0(0)+ sinh(\frac {eE\tau} {m})u^1(0) [/tex]
[tex]u^1= sinh(\frac {eE\tau} {m}) u^0(0)+ cosh(\frac {eE\tau} {m})u^1(0) [/tex]
I don't understand what I should do. First, what does u(0) mean? u(x=0)? how do I obtain these equations?
What is the relation between [tex] x^{\mu} [/tex] and [tex] x^{\nu} [/tex]?
If I define this four vector, u, and u refers to mu, than what am I to do with the other index, nu?
Thank you! I have been struggling for two days...
Noam
Given: [tex] m\frac{d^{2}x^{\mu}} {d\tau^{2}} =e{F^{\mu}_{nu}} \frac{dx^{\nu}} {d\tau}[/tex]
I have to define [tex]u^{\mu}= \frac {dx^{\mu}} {d\tau^2}[/tex]
and obtain:
[tex]u^0= cosh(\frac {eE\tau} {m}) u^0(0)+ sinh(\frac {eE\tau} {m})u^1(0) [/tex]
[tex]u^1= sinh(\frac {eE\tau} {m}) u^0(0)+ cosh(\frac {eE\tau} {m})u^1(0) [/tex]
I don't understand what I should do. First, what does u(0) mean? u(x=0)? how do I obtain these equations?
What is the relation between [tex] x^{\mu} [/tex] and [tex] x^{\nu} [/tex]?
If I define this four vector, u, and u refers to mu, than what am I to do with the other index, nu?
Thank you! I have been struggling for two days...
Noam