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Homework Help: Gravitational field

  1. Apr 23, 2005 #1
    the question is http://home.earthlink.net/~urban-xrisis/phy.jpg [Broken]


    since there are 2 masses...
    [tex]g=2 \frac{GM}{r^2+a^2}[/tex]

    my book's answer is:

    what did I do wrong?
    Last edited by a moderator: May 2, 2017
  2. jcsd
  3. Apr 23, 2005 #2

    Doc Al

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    Staff: Mentor

    OK, this is the field due to one of the masses. Note that it's a vector. What is its direction?

    Since the field contributions are vectors, they must be added as such. (You can double it only if the vectors were in the same direction.) Hint: The vertical components will cancel.
  4. Apr 23, 2005 #3

    so then g would be: [tex]g=2\frac{GM}{r^2}[/tex]

    not quite sure what to do
  5. Apr 23, 2005 #4


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    Homework Helper

    That's WRONG.
    [tex]\frac{GM\sin{\alpha}}{a^2 + r^2} - \frac{GM\sin{\alpha}}{a^2 + r^2} = 0[/tex]
    [tex]\frac{GM\cos{\alpha}}{a^2 + r^2} + \frac{GM\cos{\alpha}}{a^2 + r^2} = \frac{2GM\cos{\alpha}}{a^2 + r^2}[/tex]
    Find [itex]\cos{\alpha}[/itex]. Can you handle it from here?
    Viet Dao,
  6. Apr 23, 2005 #5

    [tex]g=\frac{2GM\frac{r}{a^2+r^2}}{a^2 + r^2}[/tex]

  7. Apr 23, 2005 #6


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    That's not correct. Recheck your [itex]cos{\alpha}[/itex].
    Viet Dao,
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