- #1

*P*on the perpendicular bisector of the line joining two objects of

*equal mass*seperated by a distance of

*2a.*

So:

[MASS] ---------------- 2a ------------------[MASS]

.......|

.......r

.......|

.......|

.......P

To calculate the resultant field, i assumed that the x direction of the resultant field is 0. Since the masses are equal, and therefore exert equal but opposite forces. Hence Resulant(X) = 0 N.

The y direction, according to my calculations, has a resultant field of [tex]\frac{2GM}{r^2}[/tex]. Since mass 1 exerts a force of [tex]\frac{GM}{r^2}[/tex] and so does mass 2.

Shouldn't the resultant gravitational field be the field in the y direction i calculated and mentioned above?

The correct answer is [tex]\frac{2GMr}{(a^2+r^2)^{3/2}}[/tex] towards the center of mass. HOW?