Compue the magnitude and direction of the gravitational field at a point(adsbygoogle = window.adsbygoogle || []).push({}); Pon the perpendicular bisector of the line joining two objects ofequal massseperated by a distance of2a.

So:

[MASS] ---------------- 2a ------------------[MASS]

...................................|

...................................r

...................................|

...................................|

...................................P

To calculate the resultant field, i assumed that the x direction of the resultant field is 0. Since the masses are equal, and therefore exert equal but opposite forces. Hence Resulant(X) = 0 N.

The y direction, according to my calculations, has a resultant field of [tex]\frac{2GM}{r^2}[/tex]. Since mass 1 exerts a force of [tex]\frac{GM}{r^2}[/tex] and so does mass 2.

Shouldn't the resultant gravitational field be the field in the y direction i calculated and mentioned above?

The correct answer is [tex]\frac{2GMr}{(a^2+r^2)^{3/2}}[/tex] towards the center of mass. HOW?

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# Homework Help: * Gravitational Field

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