Gravitational Flux in Black Holes: Can it Escape the Event Horizon?

In summary: I realize I may not have answered your question. Gravitational flux as you describe it isn't all that meaningful either, however. The speed of light is something intrinsic to the space, and the "dissemination" is merely a deformation of that space. You can talk about small perturbations of the metric, and those travel at speed c (gravity waves). But it isn't meaningful to ask how fast large perturbations are moving, because that's like asking how fast space is moving. Moving relative to what?What is the difference between a "small" and a "large" perturbation of the metric? I don't understand how that's a meaningful distinction.The thought experiment is a system
  • #1
redtree
285
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According to GR, how do changes in the mass of an energy density become reflected in its gravitational field?

Is the dissemination of the change in mass throughout the gravitational field c-limited?
If so, what geodesic does the dissemination of the change travel. Is the geodesic the same as that of a photon?
If the geodesic is different than that of a photon, then does gravitational flux travel outside the manifold of space-time as described by GR?
If the geodesic is the same, then may the gravitational flux travel faster than c?

Please consider this problem of gravitational flux within the context of a black hole:

In a black hole, photons cannot escape the event horizon due to the curvature of space-time (the geodesic). Can gravitational flux travel beyond the event horizon? If so, how? Does gravitational flux travel a different geodesic from photons, i.e., "outside" of the space-time manifold? Does gravitational flux travel faster than c? What gives?
 
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  • #2
It is not very meaningful to talk about gravitational flux. I'll tell you why. Something like electric current satisfies [tex]\nabla_\mu J^\mu = 0[/tex], and so you can calculate the net flux of charge leaving a volume from a continuity equation
[tex]\tfrac{\partial Q}{\partial t}[/tex] using the divergence theorem, evaluating [tex]n_i J^i[/tex] on the boundary.

But the divergence theorem only holds for the divergence of a vector, not a tensor. So even though in GR we have [tex]\nabla_\mu T^{\mu\nu} = 0[/tex] to help us keep track of where mass and energy is going, you can't always neatly define the total amount of mass/energy in a system, because you can't meaningfully do that integral over the boundary. There are highly symmetric cases where you can, but in most cases you can't. It basically follows from the fact that the gravitational field itself carries energy.

I realize I may not have answered your question. Gravitational flux as you describe it isn't all that meaningful either, however. The speed of light is something intrinsic to the space, and the "dissemination" is merely a deformation of that space. You can talk about small perturbations of the metric, and those travel at speed c (gravity waves). But it isn't meaningful to ask how fast large perturbations are moving, because that's like asking how fast space is moving. Moving relative to what?
 
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  • #3
What is the difference between a "small" and a "large" perturbation of the metric? I don't understand how that's a meaningful distinction.

The thought experiment is a system of two objects, on a black hole and the other a mass a distance from the black hole beyond the event horizon of the black hole. When I referred to speed, I meant relative to the black hole.

I'll rephrase the question: Assume a change in the mass of the black hole. This will cause a change in the gravitational field of the black hole. How does information relating to the mass change of the black hole reach the location in space-time of the second mass? Remember, the second mass sits beyond the event horizon of the black hole. To reach that location, does the "gravity wave" (or "gravitational flux" or "probability current" or whatever you want to call it) travel the same geodesic that a photon would travel to that location? If so, how can the gravitational wave reach the location and not the photon if both travel at c? And if the gravitational wave travels a different path than that which a photon would travel, then how is that possible?
 
  • #4
redtree said:
According to GR, how do changes in the mass of an energy density become reflected in its gravitational field?
Mass-energy directly couples to the gravitational field. Changes are often called gravitational waves.

redtree said:
Is the dissemination of the change in mass throughout the gravitational field c-limited?
Yes.

redtree said:
If so, what geodesic does the dissemination of the change travel. Is the geodesic the same as that of a photon?
I think you have a misconception here. Geodesics are spacetime paths not paths in space that change in time due to changes in the field. So in other words the complete past and future of a geodesic is already fixed in the manifold. Of course particular observers "see" those spacetime geodesics in components of space and time and can observe changes.

redtree said:
In a black hole, photons cannot escape the event horizon due to the curvature of space-time (the geodesic). Can gravitational flux travel beyond the event horizon? If so, how? Does gravitational flux travel a different geodesic from photons, i.e., "outside" of the space-time manifold? Does gravitational flux travel faster than c? What gives?
Photons inside the event horizon are on a trapped surface that is contracting, so they cannot "escape". Also here, all the geodesics are all fixed in spacetime, which is the reason that a black hole can only exist in a closed universe.
 
  • #5
Errata: Also here, all the geodesics are all fixed in spacetime, which is the reason that a black hole cannot exist in a closed universe.
 
  • #6
"Errata: Also here, all the geodesics are all fixed in spacetime, which is the reason that a black hole cannot exist in a closed universe."

Hmm, can you write down your assumptions for this statement.
 
  • #7
Haelfix said:
"Errata: Also here, all the geodesics are all fixed in spacetime, which is the reason that a black hole cannot exist in a closed universe."

Hmm, can you write down your assumptions for this statement.
There would simply be not enough time to form a complete black hole in a closed universe. For instance in the case of a "last drop in the bucket" light ray approaching an almost completed black hole at least one spacetime coordinate would approach infinity in all orthogonal coordinate charts when the ray is about to cross, let alone pass, the attempted formation of an event horizon. By the "time" it is "really close" the universe would collapse already.
 
  • #8
Rephrasing the question

I'll rephrase the question again: Assume a change in the mass of the black hole. This will cause a change in the gravitational field of the black hole. How does information relating to the mass change of the black hole reach the location in space-time of the second mass? Remember, the second mass sits beyond the event horizon of the black hole. To reach that location, does the "gravity wave" (or "gravitational flux" or "probability current" or whatever you want to call it) travel the same path that a photon would travel to that location? If so, how can the gravitational wave reach the location and not the photon if both travel at c? And if the gravitational wave travels a different path than that which a photon would travel, then how is that possible?
 
  • #9
redtree said:
I'll rephrase the question again: Assume a change in the mass of the black hole. This will cause a change in the gravitational field of the black hole. How does information relating to the mass change of the black hole reach the location in space-time of the second mass?
In steps. The additional mass is coming from somewhere else right? So, when it moves towards the black hole, sub lightspeed, the field is adjusted appropriately. Think you are in the middle of a large trampoline and someone, slowly, approaches you from the edge.

Things are more complicated if case we have the equivalent of a sonic boom for masses traveling faster than light, but these configurations are not considered physical.

redtree said:
Remember, the second mass sits beyond the event horizon of the black hole. To reach that location, does the "gravity wave" (or "gravitational flux" or "probability current" or whatever you want to call it) travel the same path that a photon would travel to that location?
Remember that in addition to coupling to itself, the gravitational field couples to mass-energy. To stay with the trampoline example, each local part of the trampoline knows how to bend, it does not need signals from the center or the edges.

I think your confusion comes from the idea of gravitational waves, don't take the term waves too literally. The spacetime manifolds of all possible universes in general relativity are not in motion, there is notion of a wave in spacetime.
 
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  • #10
You can have eternal black holes np. Also the bit about black holes taking forever to form is often stated but probably not a physical reality, and simply an artifact of an idealized mathematical setup and coordinate mumbo jumbo.

Does anyone doubt that their are stellar black holes that 'exist' at the moment?
 

1. What is gravitational flux in general relativity?

Gravitational flux in general relativity refers to the flow of gravitational force through a given surface. It is a measure of the strength and direction of the gravitational field at a particular point in space.

2. How is gravitational flux calculated in general relativity?

In general relativity, gravitational flux is calculated using the Einstein field equations, which relate the curvature of spacetime to the distribution of matter and energy within it. These equations take into account the effects of both mass and energy on the curvature of spacetime.

3. How does gravitational flux differ from electromagnetic flux?

Gravitational flux and electromagnetic flux are two different types of flux. While gravitational flux is a measure of the strength of the gravitational field, electromagnetic flux is a measure of the strength of the electromagnetic field. Additionally, gravitational flux is affected by both mass and energy, while electromagnetic flux is only affected by electric charge.

4. Can gravitational flux be observed or measured?

Gravitational flux cannot be directly observed or measured, as it is a theoretical concept in general relativity. However, its effects can be observed through phenomena such as gravitational lensing and the motion of celestial bodies.

5. How does gravitational flux affect the behavior of objects in space?

Gravitational flux is responsible for the force of gravity, which affects the motion of objects in space. The strength and direction of gravitational flux determine the trajectory of objects and their interactions with other objects in the universe.

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