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(a) through what distance does it accelerate before its release?

(b) What force does the pitcher exert on the ball?

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- Thread starter Amanda567
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(a) through what distance does it accelerate before its release?

(b) What force does the pitcher exert on the ball?

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PhanthomJay

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Sorry!

I know that gravitational force is Fg=mg

And Vxf=Vxi + axt for constant a

I know that gravitational force is Fg=mg

And Vxf=Vxi + axt for constant a

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PhanthomJay

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Ok, those 2 equations are useful. Try answering the first part of the question first,

If the ball starts from rest, through what distance does it accelerate before its release?

From your kinematic equation, you can solve for the acceleration, as long as you substitute in the correct given variables for the initial velocity of the ball starting at rest, and the final velocity of the ball as it leaves the thrower's hand. But then you'll need another one of the kimematic equations to solve for the distance. It would be a bit easier to start right off with the constant acceleration kinematic equation that relates distance with the given initial and final velocities and given time (t). But either way, what do you get for an answer for the distance the ball moves while it is still in the thrower's hands?

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PhanthomJay

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