Gravitational Force

1. Nov 25, 2005

DarkIndiglo

See Attached Word Document

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2. Nov 25, 2005

Integral

Staff Emeritus
This is pretty trivial algebra. If you are having trouble with this you need to find some help with your math.

$$F_g = \frac {G M_1 M_2} {r^2}$$

I will do r^2 for you, you should be able to puzzle out the rest.
Multiply both sides by $r^2$
$$F_g r^2 = \frac {G M_1 M_2 r^2} {r^2}$$

Cancel the $r^2$ in the Right hand side.

$$F_g r^2 = G M_1 M_2$$

Now divide both sides by $F_g$

$$\frac {F_g r^2 } {F_g} = \frac {G M_1 M_2} {F_g}$$

Now cancel the $F_g$ in the Left hand side to get

$$r^2 = \frac {G M_1 M_2} {F_g}$$

Similar operations will isolate the other quantities you need.

3. Nov 26, 2005

DarkIndiglo

Hehe
Thanks alot, I just couldn't seem to rearrange this :rofl: