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Gravitational force

  1. Nov 29, 2007 #1

    klm

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    edit- nevermind i figured it out
     
    Last edited: Nov 29, 2007
  2. jcsd
  3. Nov 29, 2007 #2

    rock.freak667

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    If you draw in the directions of the forces with respect to the 20kg mass....where is the resultant?
     
  4. Nov 29, 2007 #3

    klm

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    i found the two forces acting on the 20 kg ball and then i just did the pythagorean theorem to find the hypotenuse which would be the resultant since they are perpendicular
     
  5. Nov 29, 2007 #4

    klm

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    please can someone help!
     
  6. Nov 29, 2007 #5

    rock.freak667

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    Well the resultant force you found, was it the correct answer?
     
  7. Nov 29, 2007 #6

    klm

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    yes it is correct for the 20 kg mass
     
  8. Nov 29, 2007 #7

    rfg

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    the equation arctan(y/x) will give you the measure of the angle off the x-axis in the counter clockwise direction.
     
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