Gravitational Potential and Total Energy

  • Thread starter cde42003
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  • #1
cde42003
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Two stars with the mass and radius of the sun are separated by distance 10*r_sun, measured between their centers. A 10,000 kg space capsule moves along a line between the stars.

Suppose the space capsule is at rest 1.0 m closer to one star than the other. What will be the speed of the space capsule when it meets its ultimate fate?

Can anyone help with this problem? I thought that you need to to use the energy equation K1+U1=K2+U2 but can seem to get the correct answer.

My work
let mass capsule= m_c, mass stars= m

.5*m_c*0^2 - 2((G*m*m_c)/(5*r_sun)) = .5*m_c*v^2 - ((G*m_c*m)/(r_sun)) - ((G*m_c*m)/(9*r_sun))

Let me know what I did wrong. Thanks
 

Answers and Replies

  • #2
quasar987
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You could simple calculate the work done by the gravitational force of each stars in the capsule going from 0 to 4R (i.e. when the capsule meets the surface of the star). Add those (actually they will substract). This is the change in kinetic energy of the capsule.
 
  • #3
cde42003
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quasar987, I am not following you. Can you explain your method in more detail?

Any other options out there?
 
  • #4
StatusX
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Your equation looks right, make sure you did the math correctly.
 
  • #5
shyboy
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the change in the potential energy due to interaction with the first star

U1=-GMm(1/R-1/5R)

the change in the potential energy due to ineraction with the second satar
U2=-GMm(1/9R-1/5R)

the total change in the potential energy u=U1+U2 is equal kynetic energy of the capsule

P.S. BTW, the answer does not depend on the capsule's mass
 
Last edited:
  • #6
cde42003
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Thanks to everyone. I got the answer.
 
  • #7
SpaceTiger
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It's worth mentioning that this is not the way the three-body problem is typically treated. Why? Well, it's simply because the situation is not stable. That is, two stationary stars in close proximity will move towards one another. In fact, you could be a smartass and tell your teacher that the "correct" answer to this problem is wrong because you'd have to take into account the changing potential as a result of the stars moving towards one another, but I wouldn't recommend it. :tongue2:

Generally, when we treat the three-body problem in astronomy, we consider two stars in orbit about their center of mass. In order to simplify the problem, we generally move to a corotating frame; that is, we continually rotate the coordinate system so that the stars remain at the same points in the space. Unfortunately, when we do this, we sacrifice many of the simplicities of classical mechanics, the most important one being the conservation of energy. That is, a particle's (or spaceship's) energy in a time-varying potential is not necessarily conserved.
 

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