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jbmolineux

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- Thread starter jbmolineux
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- #1

jbmolineux

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- #2

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Not reallly. It doesn't matter how a force is related to distance between the objects, acceleration (by definition) is (distance/second)/second.

- #3

rcgldr

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a = dv/dt = v dv/dr = -G (m

For an initial distance r

- #4

A.T.

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The rate at which falling bodies accelerate is the local strength of the gravitational field.

- #5

rcgldr

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For a two body system, this would be the rate of acceleration towards a common center of mass for the two body system (use the common center of mass as the source for a reference frame). Each mass accelerates towards the common center of mass based on the gravitational field of the "other" mass.The rate at which falling bodies accelerate is the local strength of the gravitational field.

- #6

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I can falsify your notion of the universality of such a connection. Consider Hooke's law, where the force is proportional to the displacement from equilibrium, i.e.

One has nothing to do with the other. One is the relationship between force and distance from the source of that force. The other is the

Zz.

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