1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Gravity and Mass

  1. Nov 11, 2013 #1
    1. The problem statement, all variables and given/known data

    A 3.0 kg spherical flask is placed on a scale and balanced. Then a ball with a mass of 5775 kg is placed directly underneath the flask, resulting in a center-to-center distance of 56.9 cm. How much mass would have to be added to the other side of the scale in order to re-balance it?

    G = 6.67 x 10^-11 Nm^2/kg^2
    m1=3kg
    m2=5775kg
    r=0.569m

    2. Relevant equations

    (G*m1*m2)/r^2 = mg

    3. The attempt at a solution

    m=[itex]\frac{G*m1*m2}{r^2*g}[/itex]

    m=[itex]\frac{(6.67*10^-11)*(3)*(5775)}{(.569)^2*(9.81)}[/itex]

    m=0.000000364 kg
     
  2. jcsd
  3. Nov 11, 2013 #2
    Do you have a question?
     
  4. Nov 11, 2013 #3
    Did I setup the equation right?
     
  5. Nov 11, 2013 #4
    It looks OK to me.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Gravity and Mass
  1. Gravity and mass (Replies: 24)

Loading...