(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

When the Earth, Moon, and Sun form a right triangle, with the Moon located at the right angle, as shown in the figure , the Moon is in its third-quarter phase. (The Earth is viewed here from above its North Pole.)

Find the magnitude of the net force exerted on the Sun.

Find the direction of the net force exerted on the Sun. Give the direction relative to the line connecting the Sun and the Moon.

2. Relevant equations

Gm_{1}m_{2}/R^{2}

F_{net}=√F_{1}^{2}+F_{2}^{2}

[tex]\theta[/tex]= inverse trig (whatever necessary)

Mass sun=1.99E30

Mass earth= 5.98E24

mass moon= 7.35E22

radius sun to moon=1.50E11

radius moon to earth=3.85E8

3. The attempt at a solution

F_{1}(Sun-Moon)=4.336E20 found by using gravity force eq.

F_{2}(sun earth)= 3.53E22, however this is wrong because it should be 3.58E22, so that means the distance between the sun and the earth at this time would have to be 1.49E11, which doesn't make since because this should be the hypotenuse, right???. So when using the sencond value for F_{2}, and using hte pythagorean theory I get F_{net}=3.57E22, which is the right answer.

NOW to find the direction,i thought you can use the cos inverse *F_{1}/F_{2}, but this turns out to be the wrong answer I have no idea what else to do. Please help!

**Physics Forums - The Fusion of Science and Community**

# Gravity force probelm

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Gravity force probelm

Loading...

**Physics Forums - The Fusion of Science and Community**