I understand time dilation in the Special Relativity.(adsbygoogle = window.adsbygoogle || []).push({});

As in the case of an orbiting Global Positioning Satellite (GPS)

Due to the speed of the GPS orbiting earth an adjustment must be made for

time running slower than the clocks down here on earth.

A few calculations some code to speed up the onboard clock - bingo In-sync

with Earth’s Master GPS clock.

But how about the formula’s for calculating the effect of gravity?

And adjusting for General relativity as well? (They had to do it.)?

Once properly measured and the impact figured. An additional

adjustment to slow down the orbiting GPS clock due to the stronger

gravity field down on the surface of Earth making the earth bound

GPS Master clock slower.

I believe the “Special Relativity increase” is smaller than the

“General Relativity decrease” required for the orbiting GPS.

As time in orbit runs fast relative to surface time.

First - what is the correct units fpr a Gravity field? other than “G”

Force / Mass? AKA, acceleration = distance per time squared?

Deep Space g= 0G = 0ft/sec/sec=9.8m/sec/sec

Earth Surface g= 1G = 32ft/sec/sec = 9.8m/sec/sec

Orbiting GPS g= <1G = <32ft/sec/sec = <9.8m/sec/sec

Once we have the units and values for: g for Earth Surface

and g’ (g prime) for the orbiting GPS satellites.

1)What is the formula to figure the faster time rate in the GPS satellite?

2)Is the formula easily derived as is the Special Relativity dilation factors?

With the proper tools, calculating the relative clock speeds of deep space,

other planets, and accelerating spaceships in next on the agenda.

The accelerating spaceship should be the hardest as I’ll need to

integrate the affect of the increase speed as well as account

for the gravitational affect of high acceleration.

Thanks RB

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# Gravity & General Relativity

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