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B Gravity loss of a rocket

  1. Dec 2, 2016 #1
    Hello all!
    Lately i have been looking at many rocket equations, and i was wondering about the gravity loss on a rocket launch. I found the formula for the gravity loss
    upload_2016-12-2_21-16-52.png
    where g is of course the gravitational acceleration, and y is the flight path angle, but can somone explane why it looks like this? How has this been deduced?
    Thanks
     
    Last edited by a moderator: Dec 2, 2016
  2. jcsd
  3. Dec 2, 2016 #2

    mfb

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    It is the component of the gravitational force along the velocity of the rocket (=the component changing the velocity), integrated over the whole rocket flight time.
     
  4. Dec 3, 2016 #3
    Okay thanks
    But why do we have to take the Angle into accound?
     
  5. Dec 3, 2016 #4

    mfb

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    Acceleration orthogonal to the direction of motion does not change the speed.
     
  6. Dec 3, 2016 #5
    Okay thank you
     
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