Gravity Meter Problem

  • Thread starter Gammage
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  • #1
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Homework Statement


A superconducting gravity meter can measure changes in gravity of the order = 1×10-11 (delta g)/g. You are hiding behind a tree holding the meter, and your 78 kg friend approaches the tree from the other side. How close to you can your friend get before the meter detects a change in g due to his presence?
Answer in units of m.


Homework Equations


I know that Fgrav = G (m1m2)/r^2 and G = 6.672e-11 Nm^2/kg^2


The Attempt at a Solution


My first thought was to assume the m2 was 1kg and set the Fgrav = 1e-11 N, but this was wrong.
 
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Answers and Replies

  • #2
Kurdt
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You are using the equation that describes the force between two objects due to gravity. What a gravity meter detects is variance in the gravitational field. What physics do you know of the gravitational field?
 
  • #3
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Very Little

I dont think we have discussed yet in class, let me check the book for any references. This is a first year Mechanics course for natural science majors.
 
  • #4
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Hmm, there is a very brief explaination in the chapter we are in showing that the field is equal to G(M)/r^2, which is simular to what i did before but this would give me N/kg, do i factor his mass in again to get some cancelations?
 
  • #5
Kurdt
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The gravitational field is basically the acceleration due to gravity and is given by

[tex] g =G\frac{M}{r^2}[/tex]

where M is the mass of the Earth. In this question you will essentially need to work out how far away the 78kg (i.e. use his mass instead of the Earths) guy has to be to have an acceleration toward him due to his own gravity of 1x10-11 ms-2.
 
  • #6
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the 1x10^-11 is mentioned in the problem as delta g divided by g. when I set g = 1x10^-11 and M = 78kg, and solved for r the answer is wrong.
 

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