Feldoh said:[tex]g_e = \frac{GM_{e}}{R_{e}}[/tex]
[tex]\frac{1}{4}g_e = g_{distant planet}[/tex]
[tex]\frac{1}{4}*\frac{GM_{e}}{R_{e}} = \frac{G*2M_{e}}{R_{distant planet}}[/tex]
[tex]\frac{1}{4*R_{e}} = \frac{2}{R_{distant planet}}[/tex]
[tex]R_{distant planet} = 8R_{e}[/tex]
Feldoh said:Yeah, looks like I was just being retarded
Dick said:S'ok. Reminds me of my post where I was strongly suggesting an OP integrate voltage over a gaussian surface to get enclosed charge. Duh.
Gravity on a distant planet can vary greatly depending on the mass and density of the planet. Generally, the larger and more massive a planet is, the stronger its gravitational pull will be. However, if a planet has a lower density, its gravity may be weaker than Earth's.
It is possible for humans to survive in a different gravitational environment, but it would depend on the strength of the gravity and how long they are exposed to it. If the gravity is significantly stronger or weaker than Earth's, it could have negative effects on the human body and require adaptations for survival.
The closer an object is to a planet, the stronger its gravitational pull will be. This is why astronauts on the International Space Station experience microgravity, as they are further from the Earth's surface. However, once an object reaches a certain distance from a planet, the gravitational pull becomes negligible.
There is no known limit to how strong or weak gravity can be on a planet. In theory, a planet could have such a high mass and density that its gravity would be strong enough to crush objects on its surface. On the other hand, there could be a planet with such a low mass and density that its gravity is barely noticeable.
Gravity on a distant planet will cause objects to fall towards its surface at a rate determined by its strength. This is known as acceleration due to gravity. The shape and composition of the planet can also affect the behavior of objects, as well as the presence of other forces such as air resistance or magnetic fields.