Seagulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells. If a seagull drops a shell from rest at a height of 18 m, how fast is the shell moving when it hits the rocks? It seems as though I can figure out some steps of a problem, but when it comes to the rest of them, I am completly lost. Since the height is 18 feet, the initial velocity(vi) is 0, and the final velocity(vf) is 18 Gravity is 9.8 or -9.8, so I know the acceleration, so I use the equation vf=vi+at 18=0+(9.8)t 18=9.8t 18/9.8=1.836734694 or 1.84 t=1.84 vi=0 vf=18 a=9.8(gravity) or -9.8 since its moving down? t=1.84 Now that I know the following, It takes 1.84 seconds for a seagull to drop a clam from a height of 18m. Do I multiply 1.84 by 18 to get how fast the clam is moving when it hits the rocks? *Also, if there is any website out there that helps explain some problems in greater depth, or how to develop a better thought process, I dont know, please be sure to include a link!