Seagulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells. If a seagull drops a shell from rest at a height of 18 m, how fast is the shell moving when it hits the rocks?(adsbygoogle = window.adsbygoogle || []).push({});

It seems as though I can figure out some steps of a problem, but when it comes to the rest of them, I am completly lost.

Since the height is 18 feet, the initial velocity(vi) is 0, and the final velocity(vf) is 18

Gravity is 9.8 or -9.8, so I know the acceleration, so I use the equation

vf=vi+at

18=0+(9.8)t

18=9.8t

18/9.8=1.836734694 or 1.84

t=1.84

vi=0

vf=18

a=9.8(gravity) or -9.8 since its moving down?

t=1.84

Now that I know the following, It takes 1.84 seconds for a seagull to drop a clam from a height of 18m.

Do I multiply 1.84 by 18 to get how fast the clam is moving when it hits the rocks?

*Also, if there is any website out there that helps explain some problems in greater depth, or how to develop a better thought process, I dont know, please be sure to include a link!

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# Gravity Question

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