How Does Distance Affect Gravitational Force?

In summary, the weight of an apple three times as far away from the center of the Earth is 1/9th of its weight at the Earth's surface, according to the equation f = m1m2/d^2. The gravitational force is proportional to the product of the masses and inversely proportional to the square of the distance between them, but not equal to it. It is important to use variables and equations to accurately determine the ratio rather than guessing.
  • #1
Physix1233
1
0

Homework Statement


If an apple at the surface of the Earth has a weight of 1 N, its weight three times as far away from the centre of the Earth is


Homework Equations



f = m1m2/d^2

The Attempt at a Solution



1N/3times

so is it 1/3?
or since it's three times

1/9?
 
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  • #2


Physix1233 said:

Homework Statement


If an apple at the surface of the Earth has a weight of 1 N, its weight three times as far away from the centre of the Earth is


Homework Equations



f = m1m2/d^2

The Attempt at a Solution



1N/3times

so is it 1/3?
or since it's three times

1/9?

Welcome to the PF. I'd suggest that you be a little more careful and rigerous in writing the equations.

On your first equation, you are missing a constant, right? It may not be important in the calculation you are doing, but gravitational force is not equal to what you wrote as m1m2/d^2. It is proportional to that, but not equal.

And put some variables into the equation to get the ratio, don't just guess. Call the radius of the Earth R, and write the two force equations for the two spots. Then divide them -- what do you get?
 
  • #3


As a scientist, it is important to be precise and accurate in our measurements and calculations. In this case, we need to use the equation for gravitational force, which is F = G(m1m2)/d^2, where G is the gravitational constant, m1 and m2 are the masses of the objects, and d is the distance between them. We also need to consider that weight is a measure of the force of gravity on an object, so we can use the same equation to calculate the weight of the apple at a different distance from the center of the Earth.

Using this equation, we can see that if the apple's weight at the surface of the Earth is 1 N, its weight at three times the distance from the center of the Earth would be 1/9 N. This is because the distance from the center of the Earth has increased by a factor of 3, but the force of gravity decreases with the square of the distance.

Therefore, the correct answer is 1/9 N. It is important to use the correct equation and units in scientific calculations to ensure accuracy and precision.
 

What is the "Gravity weight problem"?

The "Gravity weight problem" refers to the phenomenon where an object appears to weigh more or less depending on its location in the universe.

Why does gravity affect weight?

Gravity is a fundamental force of nature that pulls objects towards each other. The amount of gravitational force between two objects is determined by their mass and distance. This force is what we perceive as weight.

Does gravity affect weight differently on different planets?

Yes, the strength of gravity varies on different planets due to differences in their mass and size. This means that an object will weigh more on a planet with a stronger gravitational pull and less on a planet with a weaker gravitational pull.

How does altitude affect weight on Earth?

As altitude increases, the distance between an object and the Earth's center increases, which results in a decrease in the gravitational force acting on the object. This means that an object will weigh slightly less at higher altitudes compared to sea level.

Can weight be completely eliminated due to gravity?

No, weight cannot be completely eliminated because gravity is a fundamental force that exists everywhere in the universe. However, the effects of gravity can be minimized in areas with microgravity or in orbit around objects with very low mass, such as in space.

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