- #1

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By looking at the graph, I know it crosses the x axis; however, I don't remember or know how to do this problem.

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- Thread starter Dustinsfl
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- #1

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By looking at the graph, I know it crosses the x axis; however, I don't remember or know how to do this problem.

- #2

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Hint: If f(x) = e^{x} + x - 2, look at f(0), f(1) and f '(x).

- #3

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I know what f(0) and f(1) are and f '(x) = e[tex]^{x}[/tex] + 1

How is that suppose to help?

How is that suppose to help?

- #4

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I know what f(0) and f(1) are and f '(x) = e[tex]^{x}[/tex] + 1

How is that suppose to help?

You mean "suppose

What does the fact that f(0) and f(1) have opposite signs tell you? What does having a positive derivative tell you? And, of course, I'm just assuming I know what your actual question was since your original post doesn't actually contain a question.

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- #6

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No extra charge for the English.

How are we supposed to know what the question was if you don't tell us? So, what was the question? And did the hints I gave you help you solve it?

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