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Homework Help: GRE Relativity Problem

  1. Sep 2, 2013 #1
    1. The problem statement, all variables and given/known data

    So to do this, I solved for the total rest energy of both particles.
    The rest energy of Kaon + K = Rest energy of Proton
    Rest energy of Proton - Rest Energy of Kaon = K
    K = P^2/2m
    ((Rest Energy of Proton - Rest Energy of Kaon)*(2*Mass of Kaon))^1/2 = P

    P = mv/(sqrt(1-v^2/c^2)

    If I do this and do all the algebra correct and solve for v, will this method give me the correct answer? I got the wrong answer but I suck at numbers X_x.

    I realize after looking at the answers on the website this is a poor way to do this problem with GRE time constraints, I just want to know if this thought process is flawed or not.
  2. jcsd
  3. Sep 2, 2013 #2
    If the rest energy of a particle is 494 MeV, and its total energy is 938 MeV, what is γ? Since [itex]γ=\frac{1}{\sqrt{1-\beta^2}}[/itex], square both sides and solve for β2 in terms of γ2. What is the value of β?
  4. Sep 2, 2013 #3
    Yeah, I see that this is the best way to do it. I was just wondering if my way works (even though it would take way longer).
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