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Grid connected transistor bridge inverter
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[QUOTE="Samtheguy, post: 4299326, member: 322344"] [h2]Homework Statement [/h2] Hi there. I was just wondering if anyone can conform that my method for this problem is correct so far? The transistor-bridge converter shown below is being used to connect a PV array to the grid. For the purpose of this coursework, you may assume that: • The PV array behaves as an ideal DC voltage source. • The grid is an ideal sinusoidal voltage source at 50 Hz. • The components are ideal and lossless. • Bipolar switching is used. The DC voltage (Vdc) is 458 V. The inverter switches at 1800 Hz and its output inductor is 4 mH. The modulation index is 0.59 at angle of 15 degrees relative to the grid voltage. The AC grid voltage is 217 V. Question - Calculate Vi (Magnitude and angle) [h2]The Attempt at a Solution[/h2] The modulation index is defined as: Mi = Vi peak (of the fundamental component) / Vdc Therefore; Vi = Mi x Vdc Vi = 0.59 x 458 Vi = 270.22V However this is a peak voltage. Hence the rms voltage is; 270.22/sqrt(2) So Vi = 191.074 V (rms) Since it is at an angle of 15 degrees to the grid voltage, use the sine rule to obtain the total length of the Vi phasor. Vi / sin(90) = 191.074 / sin(75) Vi = 197.814V So we'll say Vi = 198V at an angle of 15 degrees to the grid voltage. Is that correct?? [/QUOTE]
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Grid connected transistor bridge inverter
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