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CAF123
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Homework Statement
The interaction between the spins of the two particles in a hydrogenic atom can be described by the interaction Hamiltonian $$\hat{H_I} = A \hat{S_1} \cdot \hat{S_2}.$$ Compute the splitting of the ground state due to ##\hat{H_I}##. Both particles have spin 1/2.
Homework Equations
##\hat{S}^2 = \hat{S_1}^2 + \hat{S_2}^2 + 2 \hat{S_1} \cdot \hat{S_2}##
The Attempt at a Solution
Using the relevant equation, I can rewrite the Hamiltonian in terms of operators that are diagonal in the coupled basis.
So $$\hat{H_I} |S,S_z \rangle = \frac{1}{2} A (\hat{S}^2 - \hat{S_1}^2 - \hat{S_2}^2)|S,S_z \rangle,$$ where ##|S,S_z \rangle## is the spin part of the system wavefunction expressed as a linear combination of the coupled basis vectors.
In the ground state, the orbital part of the wavefunction will be symmetric and since we are dealing with a 2 spin 1/2 particle system, the spin part must be antisymmetric. Therefore ##|S,S_z \rangle = |0,0 \rangle.##
So, total spin is 0 and the z components of the individual electrons are oriented in different direction, with the same magnitude. So the result is, by plugging in numbers into the eqn above, ##H_I |0,0\rangle = -3/4 A \hbar^2 |0,0\rangle## So does the eigenvalue there give the interaction energy of the two electrons? Why does this correspond to the splitting?
Many thanks
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