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Grounded conductor and Electric field potential question ?
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[QUOTE="rude man, post: 5645208, member: 350494"] [B][/B] 8-14: the "spheres" quoted in the problem are actually shells. There is a central solid sphere or ball of radius R1, then infinitely thin shells of radii R2 and R3. There are thus 5 surfaces with respective charge densities (from innermost to outermost): σ1, σ2, σ3, σ4 and σ5. σ1 should be obvious. From that, σ2 should be readily calculated. That leaves σ3, σ4 and σ5. You can get 3 independent equations in these 3 unknowns. One involving σ4 and σ5 is obvious. One involving σ3 and σ4 should also be apparent; similar idea to σ1 and σ2. For the last equation, force zero E field inside the grounded shell. Having all 5 surface charge densities enables you to compute everything else.I don't think so. For one thing that would make q3 = 0. [/QUOTE]
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Grounded conductor and Electric field potential question ?
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