- #1

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I have problems forming a term.

The exercise is:

[tex] \text{Let G be a group and } x,y,z,u \in G [/tex]

[tex]\mathrm{Z\kern-.3em\raise-0.5ex\hbox{Z}}: ~ \left(x \left( \left( \left( y^{-1} \left( x^{-1} \cdot z \right) \right) ^{-1} \cdot u \right) \cdot \left( y \cdot u \right)^{-1} \right) ^{-1} \right) = z [/tex]

I kwon that I have to show that:

i.) Associative Law

ii.) Identity Element

iii.) Inverse Element

If I look the term it is clear that I have to form it such that I only have z=z and the other elements x,y,u should be transformed into the identity because of their inverse elements.

I don't know how to form this concretely

Thanks for help

Greetings

p.s.

This is not homework or something like that. I want to dish my mathematical tools :)