##H=-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}+\frac{1}{2}m\omega^2x^2##(adsbygoogle = window.adsbygoogle || []).push({});

Parity

##Px=-x##

end ##e## neutral are group of symmetry of Hamiltonian.

## PH=H##

##eH=H##

so I said it is group of symmetry because don't change Hamiltonian? And ##e## and ##P## form a group under multiplication. Is there any way to right some representation of this group? Thx for the answer.

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# Group symmetry of Hamiltonian

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