- #1

- 15

- 0

can you show that the group of all 3 by 3 matrices

[e^t 0 u

0 e^xt v

0 0 1]

where t, u, v are in C (complex numbers) and x is in R (real number)

has no center?

Regards

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter arz2000
- Start date

- #1

- 15

- 0

can you show that the group of all 3 by 3 matrices

[e^t 0 u

0 e^xt v

0 0 1]

where t, u, v are in C (complex numbers) and x is in R (real number)

has no center?

Regards

- #2

- 15

- 0

I mean all 3 by 3 matrices with the following rows

(e^t, 0, u)

(0, e^(tx), v)

(0, 0, 1).

(e^t, 0, u)

(0, e^(tx), v)

(0, 0, 1).

- #3

matt grime

Science Advisor

Homework Helper

- 9,420

- 4

You just write down two matrices, suppose the commute and show that this implies that they are both the identity matrix.

Share: